The function h (t) = 16t² + 98t graphed below shows the height, in feet, of a kicked soccer ball as a function of time, in seconds.
I'm sorry, but I cannot graph images. However, I can explain how to interpret the graph.
The graph of the function h(t) = 16t² + 98t is a parabola. The t-axis represents time in seconds, and the h-axis represents the height of the soccer ball in feet.
The graph will start at a certain height (y-intercept) and then open upwards, forming a concave upward parabola. The height of the soccer ball will increase initially, reach a maximum point, and then start to decrease.
To find the maximum height of the ball, you can find the vertex of the parabola. The vertex has the formula t = -b/(2a), where a and b are the coefficients of the quadratic equation. In this case, a = 16 and b = 98. Plugging these values into the formula, you can find the time at which the ball reaches its maximum height.
The graph will continue to increase in height until it reaches the maximum point, and then start to decrease. Eventually, the height of the ball will reach zero when it hits the ground. To find where the ball hits the ground, you would set h(t) = 0 and solve for t. This will give you the time when the ball lands.
Overall, the graph of the function h(t) = 16t² + 98t will show the height of a kicked soccer ball as it varies with time.