Two motorcars, A and B are appraching each other . At time t=0 car A and B are at 975m. With their speeds being 30m/s2 and 17m/s2 respectively and car A passed point b for 40s and car B passes at 42s calculate accelerations
To calculate accelerations, we need to use the formula:
Acceleration = (Final Velocity - Initial Velocity) / Time
For car A:
Initial Velocity of A (uA) = 0 m/s (as it starts from rest)
Final Velocity of A (vA) = 30 m/s² (given)
Time taken by A (tA) = 40 s (given)
Acceleration of A (aA) = (vA - uA) / tA
= (30 - 0) / 40
= 30 / 40
= 0.75 m/s²
For car B:
Initial Velocity of B (uB) = 0 m/s (as it starts from rest)
Final Velocity of B (vB) = 17 m/s² (given)
Time taken by B (tB) = 42 s (given)
Acceleration of B (aB) = (vB - uB) / tB
= (17 - 0) / 42
= 17 / 42
= 0.405 m/s²
Therefore, the acceleration of car A is 0.75 m/s² and the acceleration of car B is 0.405 m/s².