Given point A (2, 4) on the triangle Quadrant I, where is the new point if the triangle is rotated 270 degrees counterclockwise?
(1 point)
Responses
(−2,−4)
left parenthesis negative 2 comma negative 4 right parenthesis
(−4, 2)
left parenthesis negative 4 comma 2 right parenthesis
(4,−2)
left parenthesis 4 comma negative 2 right parenthesis
(−4,−2)
To rotate a point counterclockwise around the origin, we can use the formula:
(x', y') = (-y, x)
where (x, y) are the coordinates of the original point and (x', y') are the coordinates of the new point.
In this case, the original point is A (2, 4).
Using the formula, we have:
x' = -4
y' = 2
Therefore, the new point after rotating 270 degrees counterclockwise is (-4, 2).