Using the properties logb(1m)=−logbm and logb(mn)=logbm−logbn, how can ln11−3lnp be condensed?(1 point)

Question

Using the properties logb(1m)=−logbm and logb(mn)=logbm−logbn, how can ln11−3lnp be condensed?(1 point)

Responses

ln(113p)
l n left parenthesis Start Fraction 11 over 3 p End Fraction right parenthesis

ln(11−p3)
l n left parenthesis 11 minus p cubed right parenthesis

ln(11−3p)
l n left parenthesis 11 minus 3 p right parenthesis

ln(11p3)

Answer 1

Using the properties logb(1m)=−logbm and logb(mn)=logbm−logbn, how can ln11−3lnp be condensed?(1 point)

To condense the expression ln11−3lnp using the given properties, we can rewrite it as ln(113p).