Find the 8th term of an exponential sequence whose first term is 3 and whose common ratio is 2
To find the 8th term of an exponential sequence, we can use the formula $a_n = a_1 \cdot r^{n-1}$, where $a_n$ is the $n$th term, $a_1$ is the first term, $r$ is the common ratio, and $n$ is the number of the term we want to find.
In this case, the first term is 3 and the common ratio is 2, so we can substitute those values into the formula.
$a_8 = 3 \cdot 2^{8-1} = 3 \cdot 2^7 = 3 \cdot 128 = \boxed{384}$.