An alternating voltage is represented by the equation v=220sin(400pie(t) .57.3)v .calculate range value of the voltage
To find the range value of the voltage, we need to find the maximum and minimum values of the voltage.
The equation v = 220sin(400πet) represents an alternating voltage. In general, the equation for an alternating voltage can be written as v = Vsin(ωt + φ), where V is the amplitude, ω is the angular frequency, t is the time, and φ is the phase shift.
In this case, V = 220, ω = 400π, and φ = 57.3.
The range of the voltage is equal to twice the amplitude (V). So, the range value of the voltage is 2V.
Therefore, the range value of the voltage = 2(220) = 440 volts.