In a triangle ABC with angle AB =9m, angle AC=6m, the side ls AB and AC are product to point Xand Y respectively such that BXY=62 AXY=51 calculate angle BC
In triangle ABC, we have angle AB = 9m and angle AC = 6m. Let's draw the triangle:
B
/\
/ \
/ \
/______\
A X C
We're given that the side AB is extended to point X such that triangle BXY has angle BXY = 62 degrees. Similarly, the side AC is extended to point Y such that triangle AXY has angle AXY = 51 degrees.
We want to find angle BC.
Since angle BXY is 62 degrees, angle ABC is supplementary to BXY. Therefore, angle ABC = 180 - BXY = 180 - 62 = 118 degrees.
Similarly, since angle AXY is 51 degrees, angle ACB is supplementary to AXY. Therefore, angle ACB = 180 - AXY = 180 - 51 = 129 degrees.
Finally, to find angle BC, we use the fact that the sum of angles in a triangle is 180 degrees. Therefore, angle BC = 180 - angle ABC - angle ACB = 180 - 118 - 129 = 363 - 118 = 245 degrees.
So, angle BC is 245 degrees.