Find the x- and y-intercepts of the graph of 2, x, plus, 3, y, equals, 342x+3y=34. State each answer as an integer or an improper fraction in simplest form.
To find the x-intercept, we set $y=0$ and solve for $x$. From $342x+3y=34$, if $y=0$, then $342x=34$, which means $x=\frac{34}{342}=\frac{17}{171}$. To find the y-intercept, we set $x=0$ and solve for $y$. From $342x+3y=34$, if $x=0$, then $3y=34$, so $y=\frac{34}{3}=\boxed{\frac{34}{3}}$.
