Tito and Michael put 1200 joules of work into pushing a box up a ramp, but only 300 joules of work is output for moving the box. What is the efficiency of the ramp?
Efficiency = output work/input work x 100
A. 25 %
B. 360,000 %
C. .25 %
D. 4 %
The efficiency of the ramp can be calculated by dividing the output work (300 joules) by the input work (1200 joules) and then multiplying by 100.
Efficiency = (300 joules / 1200 joules) x 100
Simplifying this expression, we find:
Efficiency = 0.25 x 100 = 25 %
Therefore, the efficiency of the ramp is 25%.
Answer: A. 25%