Factor 3n^3 - 6n^2 + 4n - 8.
A. (3n^2 + 4) (n - 2)
B. (n^2 + 4) (3n - 2)
C. (3n^2 - 2) (n + 4)
D. (n^2 - 2) (3n + 4)
To factor the expression 3n^3 - 6n^2 + 4n - 8, we can first check if any constant value is a factor. By substitution, we can determine that n = 2 is a root of the equation.
When we divide the equation by (n - 2), we get:
3n^2 + n + 4.
Now, we can factor 3n^2 + n + 4.
The correct factorization is:
D. (n^2 - 2) (3n + 4)