A bridge can hold a maximum of 75,000 pounds. A truck that weighs 40,000 pounds carries boxes that weigh 40 pounds each. What is the maximum number of boxes the truck can carry to cross the bridge? Express your answer as an inequality.(1 point)
b≤
The weight of the truck itself is 40,000 pounds.
Let b be the number of boxes that the truck can carry.
The weight of each box is 40 pounds.
Therefore, the weight of b boxes is 40 * b pounds.
The total weight of the truck and the boxes is 40,000 + 40 * b pounds.
This total weight must be less than or equal to the maximum weight the bridge can hold, which is 75,000 pounds.
So, we have the inequality:
40,000 + 40 * b ≤ 75,000.