The sum of 4 consecutive integers is 130
What is the third number in this sequence?
Let's assume that our first consecutive integer is x. Then, the second consecutive integer will be x + 1, the third consecutive integer will be x + 2, and the fourth consecutive integer will be x + 3.
According to the given information, the sum of these four consecutive integers is 130:
x + (x + 1) + (x + 2) + (x + 3) = 130
By combining like terms, we can simplify the equation:
4x + 6 = 130
Subtracting 6 from both sides of the equation:
4x = 124
Dividing both sides of the equation by 4:
x = 31
Therefore, the first consecutive integer in this sequence is 31. The third consecutive integer will be 31 + 2 = 33.
Hence, the third number in this sequence is 33.