The sum of 4 consecutive even numbers is 36
What is the first number in this sequence?
Let's assume that the first number in the sequence is x.
Since the numbers are consecutive even numbers, the second number would be x + 2, the third number would be x + 4, and the fourth number would be x + 6.
According to the problem, the sum of these numbers is 36. So, we can write this equation:
x + (x + 2) + (x + 4) + (x + 6) = 36
Simplifying this equation, we get:
4x + 12 = 36
Subtracting 12 from both sides, we get:
4x = 24
Dividing both sides by 4, we get:
x = 6
Therefore, the first number in this sequence is 6.