If T carries inversely as s. T=2 and s=60.(
a)find the relationship between T and s (b)find the value of T when s=90 (c) find s when T=5/2
(a) The inverse relationship between T and s can be expressed as T = k/s, where k is a constant.
To find the value of k, we can substitute T = 2 and s = 60 into the equation: 2 = k/60.
Solving for k, we multiply both sides by 60: k = 120.
Therefore, the relationship between T and s is T = 120/s.
(b) To find the value of T when s = 90, we can substitute s = 90 into the relationship we found in part (a): T = 120/90.
Simplifying the expression, T = 4/3.
(c) To find s when T = 5/2, we can substitute T = 5/2 into the relationship we found in part (a): 5/2 = 120/s.
Solving for s, we multiply both sides by s and divide by 5/2: s = (120 * 2)/5.
Simplifying further, s = 240/5 = 48.