The volume of a spherical bowling ball is 322 cubic inches. The formula for the volume of a sphere is V = fr'.
What is the approximate diameter of the bowling ball rounded to the nearest tenth of an inch? (Use 3.14 as an approximation of pi.)
• 4.3 inches
• 8.2 inches
• 8.5 inches
• 8.8 inches
The given formula for the volume of a sphere is incorrect. The correct formula is V = (4/3) * π * r^3, where V is the volume and r is the radius of the sphere.
Since the volume of the bowling ball is given as 322 cubic inches, we can equate this to the formula:
322 = (4/3) * π * r^3
To find the radius, we can rearrange the equation:
r^3 = (3/4 * 322) / π
r^3 = 241.5 / 3.14
r^3 ≈ 76.84
Taking the cube root of both sides, we find the radius:
r ≈ ∛(76.84) ≈ 4.3 inches (rounded to one decimal place)
The diameter of the bowling ball is twice the radius, so the approximate diameter is:
Diameter ≈ 2 * r ≈ 2 * 4.3 ≈ 8.6 inches
Rounded to the nearest tenth of an inch, the approximate diameter of the bowling ball is 8.6 inches. None of the provided answer choices are correct.