If the measure of ∠ABD is 112°, what are the measures of 3x+7 and 2x+5?
Since ∠ABD is an angle, it is measured in degrees.
Given that ∠ABD = 112°, we have:
3x + 7 = 112
To find the value of x, we subtract 7 from both sides and divide by 3:
3x = 112 - 7
3x = 105
x = 105/3
x = 35
Now that we know the value of x, we can find the measures of 3x + 7 and 2x + 5:
3x + 7 = 3(35) + 7 = 105 + 7 = 112
2x + 5 = 2(35) + 5 = 70 + 5 = 75
Therefore, the measures of 3x + 7 and 2x + 5 are 112° and 75°, respectively.