solve for b
6=10B+12C
To solve for b, you need to isolate b on one side of the equation.
6 = 10B + 12C
First, subtract 12C from both sides:
6 - 12C = 10B
Next, divide both sides by 10:
(6 - 12C) / 10 = B
Therefore, B = (6 - 12C) / 10
6=10B+12C
6 = 10B + 12C
First, subtract 12C from both sides:
6 - 12C = 10B
Next, divide both sides by 10:
(6 - 12C) / 10 = B
Therefore, B = (6 - 12C) / 10