Please solve these
-3x + 1≤ -47|
3x + 1 ≤ -47
12x + 1 ≤ 49
-12c + 1 ≤ 49
To solve the first inequality, -3x + 1 ≤ -47, we need to isolate the variable x.
Subtracting 1 from both sides:
-3x ≤ -48
Dividing both sides by -3 (and because we divide by a negative number, the inequality sign flips):
x ≥ 16
Therefore, the solution for -3x + 1 ≤ -47 is x ≥ 16.
To solve the second inequality, 3x + 1 ≤ -47, we also isolate the variable x.
Subtracting 1 from both sides:
3x ≤ -48
Dividing both sides by 3:
x ≤ -16
Therefore, the solution for 3x + 1 ≤ -47 is x ≤ -16.
To solve the third inequality, 12x + 1 ≤ 49, we again isolate the variable x.
Subtracting 1 from both sides:
12x ≤ 48
Dividing both sides by 12:
x ≤ 4
Therefore, the solution for 12x + 1 ≤ 49 is x ≤ 4.
To solve the fourth inequality, -12c + 1 ≤ 49, we isolate the variable c.
Subtracting 1 from both sides:
-12c ≤ 48
Dividing both sides by -12 (and because we divide by a negative number, the inequality sign flips):
c ≥ -4
Therefore, the solution for -12c + 1 ≤ 49 is c ≥ -4.