AB subtends angle O1 =38° at O, the center of the circle, and AO//BC. Determine the size of O angleA C
Since AO//BC, angle ACB is also 38°.
In triangle ABC, angle BAC + angle ABC + angle BCA = 180°.
So, angle BAC + 38° + 38° = 180°.
Angle BAC = 180° - 38° - 38°.
Angle BAC = 104°.
Therefore, the size of angle AOC (O angle A C) is 104°.