The velocity of a free falling body just before hitting the ground is 9.8 m/s,what will be the height through which it fall?
The velocity of a free falling body just before hitting the ground is equal to the final velocity (v) and can be calculated using the equation:
v^2 = u^2 + 2as
Where:
v = final velocity (9.8 m/s)
u = initial velocity (0 m/s, as the body is in free fall)
a = acceleration due to gravity (-9.8 m/s^2, as it acts in the opposite direction of motion)
s = distance fallen
Rearranging the equation, we have:
s = (v^2 - u^2) / (2a)
Substituting the values into the equation:
s = (9.8^2 - 0^2) / (2 * -9.8)
s = (96.04) / (-19.6)
s = -4.9
The negative sign indicates that the body fell downwards. Therefore, the height through which it falls is 4.9 meters.