A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point)
Responses
28 kg⋅m/s
28 kilograms times meters per second
70,000 kg⋅m/s
70,000 kilograms times meters per second
280 kg⋅m/s
280 kilograms times meters per second
7,000 kg⋅m/s
To find the impulse of the punch, we can use the formula:
Impulse = force × time
Given that the force is 1,400 N and the time is 0.02 s, we can calculate the impulse as follows:
Impulse = 1,400 N × 0.02 s = 28 kg⋅m/s
Therefore, the impulse of this punch is 28 kg⋅m/s.