What is the slope-intercept form of the equation of the line that contains the points (3, 8)
and (6, 5)
?
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To find the slope-intercept form of the equation of the line that contains the points (3, 8) and (6, 5), we need to first find the slope of the line using the formula:
slope = (y2 - y1) / (x2 - x1)
Let (x1, y1) = (3, 8) and (x2, y2) = (6, 5).
slope = (5 - 8) / (6 - 3)
slope = -3 / 3
slope = -1
Now that we have the slope of the line, we can use the point-slope form of a line to find the equation:
y - y1 = m(x - x1)
Let (x1, y1) = (3, 8) and m = -1.
y - 8 = -1(x - 3)
y - 8 = -x + 3
y = -x + 3 + 8
y = -x + 11
So, the slope-intercept form of the equation of the line that contains the points (3, 8) and (6, 5) is y = -x + 11.