What is the probability that a yellow (Y) and wrinkled (r) pea will appear from a cross of RrYy x RrYy? (B.6F)

Question

What is the probability that a yellow (Y) and wrinkled (r) pea will appear from a cross of RrYy x RrYy? (B.6F)

Question 14 options:

3/16

12/16

6/16

Answer 1

To determine the probability of a yellow and wrinkled pea appearing from a cross of RrYy x RrYy, we can use Punnett squares.

First, let's determine the possible gametes that can be produced by each parent:

Parent 1 (RrYy): possible gametes are RY, Ry, rY, and ry.
Parent 2 (RrYy): same as Parent 1.

Now, let's construct a Punnett square to determine the possible genotypes of the offspring:

RY Ry rY ry
RY RRYY RRYy RrYY RrYy
Ry RRYy RRyy RrYy Rryy
rY RrYY RrYy rrYY rrYy
ry RrYy Rryy rrYy rryy

From the Punnett square, we can see that there are 9 out of 16 possible genotypes that include the yellow trait (RY, RrYY, RrYy, RRyy, RrYy, rrYY, rrYy, RrYy, rryy) and 3 out of 16 possible genotypes that include the wrinkled trait (rrYY, rrYy, rryy).

Therefore, the probability of a yellow (Y) and wrinkled (r) pea appearing is 3 out of 16, which can be simplified to 3/16.

So, the correct answer is 3/16.