When 1.0 x 10-3 moles of CuCl2(s) are added to 1.0 L of 1.0 x 10-3 M IO3
-
, the
A Trial Ksp > Ksp and a precipitate forms
B Trial Ksp < Ksp and a precipitate forms
C Trial Ksp > Ksp and no precipitate forms
D Trial Ksp < Ksp and no precipitate forms
The answer would be B. Trial Ksp < Ksp and a precipitate forms.
Ksp represents the solubility product constant, which is a measure of the extent to which a compound can dissolve in water. When the calculated Ksp is greater than the actual Ksp, it means that the compound is less soluble than expected and will form a precipitate.
In this case, if the Trial Ksp (calculated from the concentrations of Cu2+ and Cl-) is less than the actual Ksp for CuCl2, it means that the compound is less soluble than expected and a precipitate will form.