LO bisects<NLM,LM=12,NO=3 AND LN=8. What is the value of x?
In triangle LNO, using the angle bisector theorem, we have:
LM/LO = LN/NO
12/LO = 8/3
Cross multiplying, we get:
8LO = 36
Dividing both sides by 8, we find:
LO = 36/8 = 9/2
Since LO is the bisector of angle LNM, we can say that LM/LO = LN/NO. Let's substitute the given values:
12/(9/2) = 8/3
12 * 2/9 = 8/3
24/9 = 8/3
Cross multiplying, we get:
3 * 24 = 9 * 8
72 = 72
So, the equation is true. Therefore, x = 12.