A popular dance club allows 28 customers to enter per hour. The club has to keep their occupancy below 400 at any time during the day. Currently, the club has 204 customers. If none of the customers leave, how many more hours, x, can the club continue to accept new customers? Write an inequality.
The number of customers the club can accept in x hours is given by the inequality: 28x + 204 ≤ 400.
To solve for x, we can subtract 204 from both sides of the inequality:
28x + 204 - 204 ≤ 400 - 204
28x ≤ 196
Then divide both sides of the inequality by 28:
(28x)/28 ≤ 196/28
x ≤ 7
Therefore, the club can continue to accept new customers for 7 more hours, or x ≤ 7.