A chef needs 8 potatoes and 48 ounces of meat to feed 6
people. At these rates, how many potatoes and how
many ounces of meat would the chef need to feed 22
people?
Potatoes
(number)Meat
(ounces)
A.
28170
B.
28.67170.33
C.
29172
D.
29.33176
E.
29.67176.33
To solve this problem, we can set up a proportion:
(8 potatoes / 48 ounces of meat) = (x potatoes / y ounces of meat)
Cross-multiplying, we get:
8y = 48x
Simplifying, we have:
y = 6x
Now we can substitute the number of people needed to be fed (22) into the equation:
y = 6(22)
y = 132 ounces of meat
To find the number of potatoes needed, we substitute this value into the equation:
x = y/6
x = 132/6
x = 22 potatoes
Therefore, the chef would need 22 potatoes and 132 ounces of meat to feed 22 people.
The correct answer is not provided in the options.