Find an equation of the line having the given slope and containing the given point.
m = 8/9, (2, -9)
The equation of a line is given by y = mx + b, where m is the slope and b is the y-intercept.
Given that m = 8/9 and the line contains the point (2, -9), we can substitute these values into the equation.
So, substituting m = 8/9, x = 2, and y = -9 into the equation, we get:
-9 = (8/9)(2) + b
Simplifying, we have:
-9 = 16/9 + b
To solve for b, we can subtract 16/9 from both sides:
-9 - 16/9 = b
Multiplying both terms by 9 to get rid of the fraction:
-81/9 - 16/9 = b
-97/9 = b
So the y-intercept, b, is -97/9.
Therefore, the equation of the line is y = (8/9)x - 97/9.