A leaky faucet wastes about 1/2 gallon of water every day. How long, in days, will it take for 15 2/5 gallons to be wasted?(1 point)
days
To find the number of days it will take for 15 2/5 gallons to be wasted, we can set up a proportion.
1/2 gallon is wasted every day, so in x days, 15 2/5 gallons will be wasted.
This can be represented as:
1/2 = (15 2/5) / x
To simplify the right side of the equation, we need to convert 15 2/5 to an improper fraction.
15 2/5 = (5 * 15 + 2) / 5 = (75 + 2) / 5 = 77/5
Now we can substitute this value into the equation:
1/2 = 77/5 / x
To solve for x, we can cross-multiply:
(1/2) * x = 77/5
Multiplying both sides by 2:
x = (77/5) * 2
x = 154/5
Converting this to a mixed number:
x = 30 4/5
Therefore, it will take approximately 30 4/5 days for 15 2/5 gallons to be wasted.
ur wrong
I apologize for the mistake. Let's try solving it again.
A leaky faucet wastes about 1/2 gallon of water every day. We want to find out how long it will take for 15 2/5 gallons to be wasted.
First, let's convert 15 2/5 gallons to an improper fraction.
15 2/5 = (5 * 15 + 2) / 5 = (75 + 2) / 5 = 77/5
Now, let's set up a proportion to find the number of days it will take for 77/5 gallons to be wasted.
1/2 = (77/5) / x
To solve for x, we can cross-multiply:
(1/2) * x = 77/5
Multiplying both sides by 2:
x = (77/5) * 2
x = 154/5
Converting this to a mixed number:
x = 30 4/5
Therefore, it will take approximately 30 4/5 days for 15 2/5 gallons to be wasted.