A ball falls from a tall bridge. The ball has a mass of 0.15 kg. The air density is 1.225 kg/m3
. The ball’s surface area is 0.0026 m2
. The ball’s coefficient of drag is 0.007. What is the ball’s terminal velocity?(1 point)
Responses
30.4 m/s
30.4 m/s
164 m/s
164 m/s
402 m/s
402 m/s
363 m/s
363 m/s
To find the ball's terminal velocity, we can use the equation:
v_terminal = √((2 * m * g) / (ρ * A * C_d))
Where:
- v_terminal is the terminal velocity
- m is the mass of the ball (0.15 kg)
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
- ρ is the air density (1.225 kg/m^3)
- A is the ball's surface area (0.0026 m^2)
- C_d is the coefficient of drag (0.007)
Plugging in the values, we get:
v_terminal = √((2 * 0.15 * 9.8) / (1.225 * 0.0026 * 0.007))
v_terminal = √(2.9412 / 5.768675e-8)
v_terminal = √(5.09993e+7)
Taking the square root, we get:
v_terminal = 7137.68
Rounding to the nearest whole number, the ball's terminal velocity is approximately 7138 m/s.
None of the given options are correct.
give the closest ones
The closest options provided that match the calculated terminal velocity are:
1. 402 m/s
2. 363 m/s