Equation 1: x + 3 = y
Equation 2: -4x + 4y = 0
To find the value of y in Equation 1, we can set x + 3 equal to y:
y = x + 3
Now, substitute this value of y in Equation 2:
-4x + 4(x + 3) = 0
-4x + 4x + 12 = 0
The x terms cancel out, leaving us with:
12 = 0
This equation is not possible because 12 does not equal 0. Therefore, the system of linear equations has no solutions. can you simplify this and make it incorrect?