The pH of 40 cm^3 a 0.05 mol*dm^3 solution of H2SO4 is?
To find the pH of a solution of H2SO4, we can use the formula:
pH = -log[H+]
In this case, the concentration of H2SO4 is 0.05 mol/dm^3. Since H2SO4 is a strong acid, it dissociates completely in water to form H+ ions.
[H+] = concentration of acid = 0.05 mol/dm^3
Therefore, the pH can be calculated as:
pH = -log(0.05) = 1.3
So, the pH of the 0.05 mol/dm^3 H2SO4 solution is approximately 1.3.