What is the perimeter of △PQR
with vertices P(-9,2), Q(-7,3) and R(3,2) . Round your answer to the nearest tenth. (1 point)
To find the perimeter of a triangle, we add up the lengths of all three sides.
First, let's find the length of the side PQ.
Using the distance formula, we have:
√((-7 - (-9))^2 + (3 - 2)^2) = √(2^2 + 1^2) = √4 + 1 = √5
Next, let's find the length of the side QR.
Using the distance formula again, we have:
√((3 - (-7))^2 + (2 - 3)^2) = √(10^2 + 1^2) = √100 + 1 = √101
Finally, let's find the length of the side RP.
Using the distance formula once more, we have:
√((-9 - 3)^2 + (2 - 2)^2) = √((-6)^2 + 0^2) = √36 + 0 = √36 = 6
Now, we can add up the lengths of all three sides to find the perimeter:
√5 + √101 + 6 ≈ 14.7
Therefore, the perimeter of triangle PQR is approximately 14.7.