A solution was made using 100.ml of water and 1.85 g of sodium oxalate. Each trial used 10.0mL of solution.
Titration of 10.0 mL Na2OOCCOO (aq) with HCl(aq) Conc of sodium oxalate ?
To find the concentration of sodium oxalate, we need to determine the number of moles of sodium oxalate present in the 10.0 mL solution used for titration.
First, we need to determine the number of moles of sodium oxalate in the 100.0 mL solution. The molar mass of sodium oxalate (Na2C2O4) is 134.0 g/mol.
Number of moles of sodium oxalate = mass of sodium oxalate (g) / molar mass of sodium oxalate (g/mol)
Number of moles of sodium oxalate = 1.85 g / 134.0 g/mol = 0.0138 mol
Since the 100.0 mL solution contains 0.0138 mol of sodium oxalate, and we used 10.0 mL of this solution for titration, we can determine the moles of sodium oxalate in the 10.0 mL solution.
Number of moles of sodium oxalate in 10.0 mL solution = (0.0138 mol / 100.0 mL) * 10.0 mL = 0.00138 mol
Finally, to find the concentration of sodium oxalate, we divide the moles by the volume of the solution used for titration.
Concentration of sodium oxalate = moles of sodium oxalate / volume of solution (L)
Concentration of sodium oxalate = 0.00138 mol / 0.0100 L = 0.138 mol/L or 0.138 M