When solving the problem 6^x+^3=6^2x-5
, your friend does the following:
6+(x)+3=2(2x)-5
6x+3=12x-5
8=6x
x=4/3
was this correct?
Both sides should be divided by 6 instead of multiploed by6.
The 6 needs to be distributed across all terms when solvong
Yes, this is correct. No error was made.
Whwn the bases are the same, then we can set the exponets equal to each other ans solve the equastipn
for x. In this case, both sides of the equation have a base of 6. So setting the exponents equal to each other, we get:
x + 3 = 2x - 5
To solve for x, we can subtract x from both sides and add 5 to both sides:
3 + 5 = 2x - x
8 = x
So the correct solution is x = 8, not x = 4/3 as your friend calculated.