6. Iron has a density of 7.874 g/cm3. What is the mass of a rectangular block of iron with dimensions of 3.000 cm by 4.000 cm by 5.000 cm?
To find the mass of the rectangular block of iron, we need to multiply its volume by its density.
The volume of the block can be found by multiplying its length, width, and height.
Volume = length * width * height
Given that the dimensions are:
Length = 3.000 cm
Width = 4.000 cm
Height = 5.000 cm
Volume = 3.000 cm * 4.000 cm * 5.000 cm = 60.000 cm³
Now, we can calculate the mass by multiplying the volume by the density.
Mass = Volume * Density
Density of iron = 7.874 g/cm³
Mass = 60.000 cm³ * 7.874 g/cm³
Mass ≈ 472.44 g
Therefore, the mass of the rectangular block of iron is approximately 472.44 grams.