Show an equilateral triangle with the length of its sides 4acm and 3bcm and (a+b+c)
To draw an equilateral triangle with side lengths of 4cm and 3cm, we need to find the value of (a + b + c).
An equilateral triangle has all three sides of equal length, so let's assume that all three sides of the equilateral triangle have a length of 'x' cm. Then, we have the following equations:
a = x cm
b = x cm
c = x cm
Now, we are given that side a has a length of 4 cm, and side b has a length of 3 cm. Substituting these values into the equations, we get:
4 = x cm
3 = x cm
Solving these equations, we find:
x = 4 cm
x = 3 cm
Since both values of 'x' are different, we can conclude that it is not possible to draw an equilateral triangle with side lengths of 4 cm and 3 cm.
Thus, there is no valid solution to find the value of (a + b + c) in this case.