A high school play is sold tickets to their performance and wanted to see how many tickets were adults (x) and how many were students (y). There were 50 more adult tickets sold compared to student tickets. Adult tickets were $5, student tickets were $2, and they collected a total of $950. Write 2 equations and solve this system. Final Answer: How many solutions are
Final Answer: How many solutions are there
1
Infinitly Many Solutions
No Solution
Let's set up the system of equations to solve for the number of adult (x) and student (y) tickets sold:
Equation 1: x = y + 50 (since there were 50 more adult tickets sold compared to student tickets)
Equation 2: 5x + 2y = 950 (the total amount collected from selling adult and student tickets was $950)
To solve this system of equations, we can substitute the value of x from equation 1 into equation 2:
5(y + 50) + 2y = 950
5y + 250 + 2y = 950
7y + 250 = 950
7y = 700
y = 100
Substituting the value of y back into equation 1:
x = 100 + 50
x = 150
Therefore, there is only one solution to this system of equations.