Find an equation of the line containing the given pair of points. Express your answer in the form x equals a, y equals b, or y equals mx plus b.
(0,0) and (3,8)
The equation of a line passing through two points (x1, y1) and (x2, y2) can be found using the slope-intercept form:
y = mx + b
First, let's find the slope (m) of the line using the formula:
m = (y2 - y1)/(x2 - x1)
Given points are:
Point 1: (0, 0)
Point 2: (3, 8)
Substituting the values into the formula:
m = (8 - 0)/(3 - 0)
m = 8/3
Now, we can substitute the slope (m) and one of the points (x1, y1) into the slope-intercept form to solve for the y-intercept (b):
0 = (8/3)*(0) + b
0 = 0 + b
b = 0
Therefore, the equation of the line passing through the points (0, 0) and (3, 8) is:
y = (8/3)*x + 0
Simplifying, we get:
y = (8/3)x