A bridge can hold a maximum of 75,000 pounds. A truck that weighs 40,000 pounds carries boxes that weigh 40 pounds each. What is the maximum number of boxes the truck can carry to cross the bridge? Express your answer as an inequality.(1 point) b≤
The weight of the truck is 40,000 pounds. The maximum weight the bridge can hold is 75,000 pounds.
Let's assume that the truck can carry "b" boxes. Each box weighs 40 pounds. So the total weight of all the boxes is 40 * b = 40b pounds.
To ensure that the total weight of the truck and all the boxes is less than or equal to the maximum weight the bridge can hold, we can write the inequality:
40b + 40,000 ≤ 75,000
Simplifying this inequality, we get:
40b ≤ 35,000
Dividing both sides of the inequality by 40, we get:
b ≤ 875
Therefore, the maximum number of boxes the truck can carry to cross the bridge is 875 boxes.