△JKL is given with J(−1,1), K(4,4), and L(5,1). What is the area of △JKL? Justify your response.(1 point)

Responses

Since the base JL¯¯¯¯¯¯¯ has a length of 6 and the altitude is 3, △JKL has an area of 9 units squared.
Since the base modifying above upper j upper l with bar has a length of 6 and the altitude is 3, triangle upper j upper k upper l has an area of 9 units squared.

Since the base JL¯¯¯¯¯¯¯ has a length of 6 and the altitude is 3, △JKL has an area of 18 units squared.
Since the base modifying above upper j upper l with bar has a length of 6 and the altitude is 3, triangle upper j upper k upper l has an area of 18 units squared.

Since the base JL¯¯¯¯¯¯¯ has a length of 1 and the altitude is 4, △JKL has an area of 2 units squared.
Since the base modifying above upper j upper l with bar has a length of 1 and the altitude is 4, triangle upper j upper k upper l has an area of 2 units squared.

Since the base JL¯¯¯¯¯¯¯ has a length of 1 and the altitude is 4, △JKL has an area of 4 units squared.

The correct response is: Since the base JL¯¯¯¯¯¯¯ has a length of 6 and the altitude is 3, △JKL has an area of 9 units squared.