Between which pair of rational numbers on a number line does sqrt(38) lie?

We can approximate $\sqrt{38}$ by finding two perfect squares that it lies between. Since $6^2 = 36$ and $7^2 = 49$, we know that $\sqrt{36} = 6 < \sqrt{38} < 7 = \sqrt{49}$. Therefore, $\sqrt{38}$ lies between $\boxed{6}$ and $\boxed{7}$.