Make a table for the number of virions (virus particles) that grow inside a human body. Start with one virion on the first day, and continue the table for two weeks using the formula from part a. (the formula is A(t) = Pe^(0.15t))
Day 1 is 1 for the # of Virons
Day 2-14 require you to fill it out (so please help me with that part)
To fill out the table for the number of virions that grow inside a human body for two weeks using the given formula A(t) = Pe^(0.15t), we will assume P = 1 (since we start with one virion) and t represents the number of days.
Using the formula, we can calculate the number of virions for each day:
Day 1: A(1) = 1e^(0.15*1) = 1e^(0.15) ≈ 1.162
Day 2: A(2) = 1e^(0.15*2) = 1e^(0.3) ≈ 1.349
Day 3: A(3) = 1e^(0.15*3) = 1e^(0.45) ≈ 1.562
Day 4: A(4) = 1e^(0.15*4) = 1e^(0.6) ≈ 1.816
Day 5: A(5) = 1e^(0.15*5) = 1e^(0.75) ≈ 2.128
Day 6: A(6) = 1e^(0.15*6) = 1e^(0.9) ≈ 2.514
Day 7: A(7) = 1e^(0.15*7) = 1e^(1.05) ≈ 2.99
Day 8: A(8) = 1e^(0.15*8) = 1e^(1.2) ≈ 3.577
Day 9: A(9) = 1e^(0.15*9) = 1e^(1.35) ≈ 4.299
Day 10: A(10) = 1e^(0.15*10) = 1e^(1.5) ≈ 5.185
Day 11: A(11) = 1e^(0.15*11) = 1e^(1.65) ≈ 6.273
Day 12: A(12) = 1e^(0.15*12) = 1e^(1.8) ≈ 7.608
Day 13: A(13) = 1e^(0.15*13) = 1e^(1.95) ≈ 9.243
Day 14: A(14) = 1e^(0.15*14) = 1e^(2.1) ≈ 11.244
Hence, the completed table would look as follows:
Day 1: 1
Day 2: 1.162
Day 3: 1.349
Day 4: 1.562
Day 5: 1.816
Day 6: 2.128
Day 7: 2.514
Day 8: 2.99
Day 9: 3.577
Day 10: 4.299
Day 11: 5.185
Day 12: 6.273
Day 13: 7.608
Day 14: 9.243