There are 5 people in a raffle drawing. Two raffle winners each win gift cards. Each gift card is the same. How many ways are there to choose winners? Decide if the situation involves a permutation or combination.
To determine the number of ways to choose winners, we have to decide whether order matters or not.
If order matters, then it is a permutation. In this case, since there are 5 people and 2 winners, the first winner can be chosen in 5 ways and the second winner can be chosen in 4 ways, resulting in a total of 5*4 = 20 permutations.
If order doesn't matter, then it is a combination. In this case, since there are 5 people and 2 winners, the number of combinations can be calculated using the formula for combinations: n! / (r!(n-r)!), where n is the total number of items and r is the number of items being chosen. For this situation, the number of combinations is 5! / (2!(5-2)!) = 5! / (2!3!) = (5*4*3!) / (2*1*3!) = (5*4) / (2*1) = 10.
Therefore, there are 20 permutations if order matters, and 10 combinations if it doesn't.