Write an inequality that represents the following scenario: Katlyn takes 20 minutes to walk from her house to the supermarket and back. After stepping outside her house, she takes 1 minute to tie her shoes and 2 minutes to check the route on her phone. How many trips can she take to the supermarket and back in 60 minutes
Let x be the number of trips Katlyn can take to the supermarket and back in 60 minutes.
The time it takes for one trip from her house to the supermarket and back is 20 minutes.
The time she spends on activities before starting the trip is 1 + 2 = 3 minutes.
In 60 minutes, Katlyn can spend at most 60 - 3 = 57 minutes on the trips.
The inequality representing this scenario is: 20x ≤ 57.
wrong
Apologies for the previous incorrect response.
Let's break down the time spent on each trip:
Time spent on one trip = Time to walk from her house to the supermarket and back + Time to tie shoes + Time to check the route on her phone
Time spent on one trip = 20 + 1 + 2 = 23 minutes
Now, let's find the maximum number of trips Katlyn can take in 60 minutes:
Maximum number of trips = Total time available / Time spent on one trip
Maximum number of trips = 60 / 23 = 2.6087 (rounded to 2 decimal places)
Therefore, Katlyn can take a maximum of 2 trips to the supermarket and back in 60 minutes.