A student sold candy bars and bags of popcorn for a school fund-raiser.
The student sold a total of 240 candy bars and bags of popcorn.
The price of each candy bar was $1, and the price of each bag of popcorn was $2.
The student sold $300 worth of candy bars and bags of popcorn.
How many candy bars did this student sell for the school fund-raiser?
Option A.
80
Option B.
60
Option C.
180
Option D.
120
Let's assume that the student sold x candy bars. Since the price of each candy bar is $1, the total revenue from selling the candy bars would be x * $1 = $x.
The student also sold 240 candy bars and bags of popcorn. Therefore, the student sold 240 - x bags of popcorn.
The price of each bag of popcorn is $2, so the total revenue from selling the bags of popcorn would be (240 - x) * $2 = $480 - $2x.
The total revenue from selling candy bars and bags of popcorn is $300.
Thus, the equation can be formed as follows: $x + $480 - $2x = $300.
Combining like terms, we get $480 - $x = $300.
Subtracting $480 from both sides, we get -$x = $300 - $480 = -$180.
Multiplying both sides by -1, we get x = 180.
Therefore, the student sold 180 candy bars for the school fund-raiser.
The answer is option C.
A sequence can be generated by using the equation shown, where a 1 = 12 and n is a whole number greater than 1.
A n = 1.5 + a (n-1)
What are the first four terms in the sequence?
Option A.
12 13.5 16 19.5
Option Be.
12 13.5 15 16.5
Option C.
12 13.5 16.5 21
Option D.
12 13.5 15.5 18
To find the first four terms in the sequence, we can substitute the values into the equation and apply the recursive formula.
Given a1 = 12, we can use the formula An = 1.5 + a(n-1) to find a2, a3, and a4.
a2 = 1.5 + a1 = 1.5 + 12 = 13.5
a3 = 1.5 + a2 = 1.5 + 13.5 = 15
a4 = 1.5 + a3 = 1.5 + 15 = 16.5
Therefore, the first four terms in the sequence are:
12, 13.5, 15, 16.5
The answer is Option B: 12, 13.5, 15, 16.5.