When 6.00 mol of ice at 0.0°C melts completely without changing temperature, it absorbs 36.1 kJ of energy. The experimental heat of fusion of ice is
The heat of fusion of ice is calculated by dividing the energy absorbed by the number of moles of ice that have melted.
Given:
Number of moles of ice = 6.00 mol
Energy absorbed = 36.1 kJ = 36.1 * 10^3 J
Heat of fusion of ice = Energy absorbed / Number of moles of ice
Heat of fusion of ice = 36.1 * 10^3 J / 6.00 mol
Heat of fusion of ice = 6016.67 J/mol
Therefore, the experimental heat of fusion of ice is approximately 6016.67 J/mol.