A student reasons that the area of the following triangle can also be calculated as A=12acsinA . Is the student correct? If not, why not?
A) The student is incorrect. The angle has to be between the two sides. Replacing A with B would make the formula true.
B) The student is incorrect. The area formula is A=12absinC
C) The student is correct.
D) The student is incorrect. The angle should be the same as the second side, c, so replacing the angle with C would make the formula true.