Given point A 2,4 on the triangle in quadrant 1 where is the new point if the triangle is rotated 90 degrees counterclockwise
To rotate a point counterclockwise by 90 degrees, we can use the following formula:
New x-coordinate = (Old x-coordinate * cos 90°) - (Old y-coordinate * sin 90°)
New y-coordinate = (Old x-coordinate * sin 90°) + (Old y-coordinate * cos 90°)
For point A(2,4), we have:
New x-coordinate = (2 * cos 90°) - (4 * sin 90°)
= 2 * 0 - 4 * 1
= 0 - 4
= -4
New y-coordinate = (2 * sin 90°) + (4 * cos 90°)
= 2 * 1 + 4 * 0
= 2 + 0
= 2
Therefore, the new point after rotating point A(2,4) 90 degrees counterclockwise is (-4,2).