Use the noble gas short cut to give the electron configuration of tin. In your answer, put a space between each type of orbital.
The noble gas short cut allows us to use the electron configuration of the nearest noble gas that precedes tin, which is xenon (Xe). The electron configuration of xenon is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶
To determine the electron configuration of tin (Sn), we start by listing the electron configuration of xenon, followed by the additional orbitals for tin. The electron configuration of tin is therefore:
[Xe] 5s² 4d¹⁰ 5p²